John N. Power wrote:
> This is an amplification of my first response:
>
> The current in an inductor obeys the equation E = L (di/dt).
> The voltage E is the voltage across the inductor, which is
> the difference between the input voltage Vin and the output
> voltage Vout: E = (Vin - Vout).
>
> If Vout decreases because of an increase in load current, E
> *increases*. This increase causes larger increments of current
> to flow into the inductor during the charge phase
> ( di = E * dt / L, which increases if E increases).
> The inductor integrates these larger pulses, causing the
> average current in the inductor to rise until the new standing
> current equals the new load current. This increase takes place
> *without increasing the duty cycle*. Once the currents reach
> equilibrium, the *original* duty cycle continues to maintain
> the ratio between Vout and Vin.

Nonsense again, John.
The same Vin, Vout, duty cycle, inductance, but different output
currents?
This kinda perpetual motion machine crap should be moved to [OT:]
in my opinion.

Mike.

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