I'm paranoid about this, cause I don't know where the wires run internall=
y.

Cheers,
-Neil.



On Friday 22 August 2003 22:14, John Ferrell scribbled:
> How about drilling a tiny hole in the led?
>
> John Ferrell
> 6241 Phillippi Rd
> Julian NC 27283
> Phone: (336)685-9606
> johnferrell@earthlink.net
> Dixie Competition Products
> NSRCA 479 AMA 4190  W8CCW
> "My Competition is Not My Enemy"
>
>
> ----- Original Message -----
> From: "Picdude" <picdude@NARWANI.ORG>
> To: <PICLIST@MITVMA.MIT.EDU>
> Sent: Friday, August 22, 2003 12:54 PM
> Subject: [EE:] How can I destroy select LED segments?
>
>
> I'll probably get sent off to the looney-bin for this one, but it's wor=
th a
> shot still...
>
> I'm working on a PIC circuit that will send its output to a few 7-seg
> LED's. The 7-seg displays are all part of one integrated multiplexed un=
it,
> but only one digit will need to have the DP (decimal-point) on, and it =
will
> always be on.
>
> However, I'm just one pin short, and I'd like to avoid adding more part=
s
> (by multiplexing, etc), so I thought of just running outputs to the 7 m=
ain
> segments, and hard-wiring the DP to be always on.  But this means I nee=
d to
> destroy the DP on the other digits (which will always have the DP off).
>
> So if I selectively zap each of the OFF decimal points with say 12V, ca=
n I
> selectively destroy those dp's WITHOUT destroying any other display
> segments?
> Standard logic tells me I should be okay, but I fear that there's more =
to
> it.
>
> FWIW, I found another way to solve this problem (sending the column-sel=
ect
> output of the digit with the ON DP to the DP input of the display, and
> using CA displays with NPN transistors).  But I think that burning out
> unwanted segments can be very useful for other purposes, so the questio=
n
> still stands.
>
> Cheers,
> -Neil.

--
http://www.piclist.com hint: The PICList is archived three different
ways.  See http://www.piclist.com/#archives for details.