> I just completed my first A/D conversion.  Not a complicated task, but
> unfortunately I don't understand my result.  There is a 0.5 V potential
> sitting on the my A/D pin, but the right-justified result appears as
> 0x067 in ADRESL while ADRESH is clear (as expected).  My question is:
> How do I interpret this result in terms of the known voltage on my A/D
> pin?

The 10 bit A/D result in your case is written into the 16 bit value
ADRESH:ADRESL.  This value is 67h, which is 103 decimal.  103/1023 = .1007
of full range.  Assuming you didn't use either Vref and Vdd is 5V, that
means the A/D input voltage was 5V * .1007 = 503mV.  It looks like
everything went perfectly.

This is of course all explained in the manual.  What part specifically are
you having a problem with?


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