Alex Kilpatrick wrote:
> If I set up the pin as an output, then it is
> high-impedence, correct?  So, to the circuit it is not there?
>
> (I always hate putting EE on my subject line.  I have an undergrad
> degree in EE, so I always feel like I should know this)  :-)

Yes, you should.  This is very basic.  Where is this degree from?

CMOS inputs are high impedence.  Outputs drive the line, so are inherently
"low" impedence.


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