Hi Sean,

According to the chart, acceleration due to gravity (at sea level) is:
    42'N -> 32.16329 feet/second^2 or 980.3489 cm/second^2
and
    43'N -> 32.16625 feet/second^2 or 980.4391 cm/second^2

To compensate for local altitude, use this formula:

    g(ll) = g(sl) - 0.3086 * h

where
    g(ll) = acceleration due to gravity at altitude "h" in cm/s^2
    g(sl) = acceleration due to gravity at sea level in cm/s^2
    h = altitude in kilometers

For example, if you are at 1600 meters altitude then

    g(ll) = 980.3489 - 0.3086 * 1.6
    g(ll) = 979.8551 cm/s^2

I hope this helps out!

John




> Hi John,
>
> Sorry for taking a few days to reply myself. Yes, that's what I'm looking
> for. A co-worker here at Cornell finally found a site on the web that let
> you look this up. I don't offhand remember the value we got for the Cornell
> Campus but could you tell me what value your book has for
> 42.48N  76.47W?
>
> Probably the table in your book simply uses one of the approximation
> formulas (given how coarse the data is and the fact that you said it is
> only for latitude).
>
> Thanks!
>
> Sean

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