On Wed, 7 May 2003, David Harris wrote: > Hi- > I just played with it on Win98 -- > For the example, I found 24750 ohms and 0.01uF came out best. > Now, what if we have an active circuit on the output, as we will > probably have to buffer the signal anyway -- can we do better? Sure! If you have an ideal integrator then you can simplify the software algorithm. It's much easier for a PIC to predict the output of an integrator than an RC circuit when a step function is applied to the input. Scott -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads