Not specifically w.r.t. GPS, but from a mathematical perspective...

If you're suggesting averaging by averaging points A & B, then the result=
 of=20
that with C, then with D, etc, that would be an incorrect definition of t=
he=20
term "average".  Avg(A,B,C) !=3D Avg(A,Avg(B+C)).  For example, the avera=
ge of=20
7,8,9 =3D 8.  Avg(Avg(7,8) , 9) =3D Avg(7.5,9) =3D 8.25.  Bzzzt!

So take all lats and avg those, take all lons and avg those, and that sho=
uld=20
be the result.

Or maybe there's something specific to GPS that makes this all just a loa=
d of=20
cr*p?

Cheers,
-Neil.


On Thursday 24 April 2003 21:49, rad0 wrote:
> how exactly would I calculate an average of a fixed gps reciever
> to eventually get a more accurate lat/lon ??
>
> if you take two lat/lon's average, then do this with the very next
> available lat/lon
> is this any good?
>
> or if you take 10 lat/lon's get average then average this with the next=
 ten
>
>
> what's the best way to do this?
>
>
> thanks

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