The problem in your specific case is that you are attempting to turn on your FET at 80kHz I think you said with different size gate resistors. 80kHz is relatively fast and you may not be charging the gate capacitance fast enough to "fully" turn on the FET with the PIC output. Therefore, the FET is operating in its linear region which means it isn't "fully" on and the Drain-Source Resistance is still quite high which is why your FET is heating up. PowerDiss = Rds * Ids. You'll need to add another driving circuit for your FET. D > So what happens when you slowly drive the gate..does the conductance > increase with the gate voltage such that you reach the final > on mode? In > other words, a soft start circuit. If I wanted to minimize > the spikes on > the output (such as capacitors charging) then is this the > proper method? > > > _________________________________________________________________ > Help STOP SPAM with the new MSN 8 and get 2 months FREE* > http://join.msn.com/?page=features/junkmail > > -- > http://www.piclist.com hint: The list server can filter out subtopics > (like ads or off topics) for you. See http://www.piclist.com/#topics > -- http://www.piclist.com hint: The PICList is archived three different ways. See http://www.piclist.com/#archives for details.