From: "Olin Lathrop" > > How is this? When you power up the circuit, your capacitor will be > > discharged. Which means that the positive end will be at either 0V > > (if the negative end is tied to ground) or at 5V (if it's tied to > > 5V). > Not from the charge pump's point of view. Yes, if the circuit has been off > a long time the voltage accross all the caps will be 0. However, the +10V > supply is brought to +5V directly by the +5V supply. This happens as the > +5V supply comes up, and is not done by the charge pump, and therefore > doesn't slow it down getting to +10V. Yes it does... It all depends on the ammount of power available on the +5 rail and the max power the max can push out to the cap at power-up. This can cause a slight delay compared to the reccommended coupling. Just look at the charge through a digital/capturing oscilloscope. Its a lot of fun! KreAture -- http://www.piclist.com hint: To leave the PICList mailto:piclist-unsubscribe-request@mitvma.mit.edu