> Also, the first of the two links you sent, Russell, claims that the cap on > the output of the inverter, along with the drive limit resistor, form a > simple RC voltage divider, and you can compute the voltage level at this > point based on this. I don't think this is an accurate way of describing it > since it is also connected to the (inductive) xtal which may alter the > impedance at that junction considerably. Yep. It's all black magic. Alas, the spells vary depending on what book you look in. It is possible for the oscillator signal to get outside the rails slightly. Add a parallel inductor (as I have had to do on one design to compensate for a manufacturers inability to build microprocessors which meet specification)(not PIC) and the output can get substantially outside rail. I agree with the "add the two capacitors in series" idea, with ground being independent for small signal models. But, as you note, in the real world other factors enter the model. If you have a near rail to rail swing and the capacitors are substantially unequal and you ground their midpoint that will skew the signal wrt the supply rails and carry one extreme outside the supply rail. Get a diode drop too high or too low and interesting results will occur. Russell -- http://www.piclist.com#nomail Going offline? Don't AutoReply us! email listserv@mitvma.mit.edu with SET PICList DIGEST in the body