> Note quite. It's actually the net capacitance that's expected to be in
> parallel with the crystal. This includes the series combination of your
> external capacitors, plus the distributed capacitance of the PCB traces
> and the chip pins.

Are you really sure, Dave?  I thought (although can't find reference right
now) that the capacitance rating was the load capacitance required on the
output of the crystal to produce the proper phase shift at the rated
frequency.  I further thought that the capacitor on the input side of the
crystal was only there to soften the edges and reduce the harmonics from
the driver.


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