>>
>> ~12V in-|=2k=|--|----|-----|------PIC pin
>>                 |    |     |
>>                 Z    C     R
>>                 |    |     |
>>                 |----|-----|------ GND
>>
>> Z= 5,1V
>> C= 100n
>> R= 100k

>OK.
>I assume there is a switch there somewhere or that the AC turns off and on.
>The 2K is far lower than it needs to be if you use a 100K pullup.
pulldown, right? :)
>Not a problem - just doesn't need to be that low.

Oops :)
I just found out that once again I was very unclear! :)
What I meant was about 12V NOT AC 12V. My mistake! Sorry about that!!!

The reason I have only 2k is becourse the 12V is comming from an
serial-port, and is not always 12V and I noticed that with a laptop and 10k
instead of 2k the Zener voltage was below 4.5V.

Actually a do have a diode before the 2k resistor in case of negative
voltage but I didn't think that was relevant here.

Anyway, thanks for your help!
/Andreas

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