Andre,

My apologies, I should have been a little more clear. When I said
W=32 I was thinking, but not writing, packed BCD 32, or 0x32.
I'm not really sure how that should be written.

However, the status bits DC and C  should both
be set to '1' before the DAW in order to simulate the results
an addition (ADDWFC or similar) of two packed BCD
numbers, 99.+ 99 in this case.

BTW I heard from Microchip already, not much but they said
they will look into it. Not sure what that means but it's a start.

Mike Jones

----- Original Message -----
From: "Andre Abelian" <engelec@EARTHLINK.NET>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Tuesday, February 04, 2003 3:59 PM
Subject: Re: [PIC]: DAW how it works (BCD)


> Mike,
>
> If Wreg = d'32' that is 0x20
> After DAW every thing remains the same d'32' and C=0 DC=0
> The only time DC will be 1 when goes over d'15' and
> C will be 1 if your number goes over 99.
>
> Andre Abelian
>
>
>
> -----Original Message-----
>
>
> Thanks for setting that up and testing, it's appreciated.
>
> I don't know how hard it is to set up but you might try the following;
> DC= 1
> C   = 1
> W = 32
> (This would be the result of adding 99 + 99)
> Then execute the 'DAW
> The result should be (according to Microchip for the 18F series)
> DC= 1
> C   = 0
> W= 98
>
> Using a 18F452, I arrived at the results (as above) that Microchip
> said you should get.
>
> I found a question nearly identical to mine in the Microchip
>  Developers conference and their answer was as above. I still
> don't know why but I asked. Maybe I'll get a response in a day or
> two.
>
> http://asp.microchip.com/webboard/wbpx.dll/~devtools
> Search for DAW
>
> Thanks again
>
> Mike Jones
>
> ----- Original Message -----
> From: "Andre Abelian" <engelec@EARTHLINK.NET>
> To: <PICLIST@MITVMA.MIT.EDU>
> Sent: Tuesday, February 04, 2003 2:46 PM
> Subject: [PIC]: DAW how it works (BCD)
>
>
> > Hi to all,
> >
> > I did some test using DAW instruction on MPLAB ICE2000
> > and this is the result.
> >
> >         Movlw           0x0F            ; w reg has d=15: B=00001111
> >         DAW                             ; do decimal adjustments
> >         Movwf           BCD_REG ; BCD_REG has d=21 b=00010101 C=0
> >
> >
> > Second digit (F)                05
> > First  digit (0)     + 01
> > Result               015        ; 0 means C=0: 1 is bits 4,5,6,7  and
> >                                                         5 is bits
> > 0,1,2,3
> >
> >
> > Now lets deal with higher numbers
> >
> >         Movlw           0xEF            ; w reg has d=239: b=11101111
> >         DAW                             ; do decimal adjustments
> >         Movwf           BCD_REG ; BCD_REG has d=85 h=55 b=10101010
> >
> >
> > Second digit (F)                15      ; decimal
> > First  digit (E)     + 14       ; decimal
> > Result               155        ; 1 means C=1: 5 is bis 4,5,6,7  and
> >                                                         5 is bits
> > 0,1,2,3
> >
> >
> > Andre Abelian
> >
> > --
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> >
>
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