At 09:13 AM 1/15/03 -0500, you wrote:
> > Note that as the A/D is switched between channels, you actually have a
> > charge pump from one channel to the next.  A newly selected channel is
> > connected to the same internal capacitor that the previous channel was
> > connected to.  This actually creates an equivalent resistance from the
> > previous channel voltage to the current channel pin.  This equivalent
> > resistance is proportional to the period between selections of the same
> > channel.  None of this should matter, however, if each channel's source
> > impedence is 10Kohms or less and you are waiting the proper acquisition
> > time.
>
>Oops.  I meant to say that the equivalent resistance is *inversely*
>proportional to the channel selection period (proportional to frequency of
>the channel being selected).

I think you were right the first time.

Best regards,

Spehro Pefhany --"it's the network..."            "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog  Info for designers:  http://www.speff.com

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