Hi, i tried this example on PIC16F84, that counts the number of
changes on a switch. It's easy to understand the btfss and btfsc parts
that waits for changes on the switch and then adds the change to the
counter.

        But i didn't realize why we need to delay a bit (ANTIREBOND) when
the switch is changed. According to the example's text, it's because of
mechanical problems of switches...anyone could give me a better
explanation for the need of this delay?


LOOP            btfss   PORTA,0
                goto    LOOP
                call    ANTIREBOND

LOOP2           btfsc   PORTA,0
                goto    LOOP2
                call    ANTIREBOND


                incf    COUNTER,f
                movf    COUNTER,w
                movwf   PORTB


                goto LOOP


ANTIREBOND      bcf     INTCON,2

                movlw   0xB0

                movwf   OPTION_REG

DEL             btfss   INTCON,2
                goto    DEL
                return




[]s Rafael.
http://grad.icmc.sc.usp.br/~rva

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