A pointer to the function:

int foo(int bar)

can be declared simply:

int (*myFooPtr)(int);

I often choose to create a typedef:

typedef int (*fooptr_t)(int);

then I can:

fooptr_t    myFooPtr;
fooptr_t    yourFooPtr;

Bob Ammerman
RAm Systems

----- Original Message -----
From: "Brendan Moran" <annirack@SHAW.CA>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Wednesday, December 11, 2002 12:40 AM
Subject: function pointer syntax in C/C++


> On most C syntax I do just fine, but function pointers are always a
> head-scratcher for me.
>
> If I wanted to declare a pointer to this function:
>
> int foo(int bar);
>
> What would be the syntax for the declaration?
>
> The best I came up with was this:
>
> (int)(*)(int) pfoo = &foo;
>
> but that doesn't compile.
>
> Thanks,
> --Brendan
>
> --
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