>Hello,
>     I am in need to divide a 12.5 Mhz clock by 163. How can this be
>done with a counter? I know that if this division were a power of two,
>then it would be very straight forward, but this is not my case at all.
>Any pointers will be greatly appreciated. -Vic

If only it were an even number this would be straightforward.  But
you had to pick 163.    Otherwise you divide by 2 at the end and
the result is square.  I don't suppose you could fudge it to
162 or 164...

Barry

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