This is an isolated DC-DC converter, used to produce the -9V supply for BNC and AUI (D15) connections. the part number implies that it's a 5V to 9V converter (this is almost universal), so I doubt it's running from 12V (unless through a 5v regulator) On Sat, 2 Nov 2002 23:14:38 -0600, you wrote: >Hi all. So, in my PIC&Ethernet quest, I have aquired a bunch of NE2000 >cards based on the RTL8019AS chip. Some of them clearly have no >connection to the +12V pin on the ISA bus - a bonus as then all I need >is +5V. I do have a few cards that the +12V line is connected to though. >However, they go to a component that I can't identify. I tried chipdir >and a google search, and although there were some matches, there was no >ID of what it might be. The closest thing was a product table for >transformers. Question is, why would a transformer need +12? Anyway, the >part number seems to be CFUS0509-C. It's a 24 pin wide DIP, and it's a >big tall block, not an IC. > >Any ideas? I know that figuring out what it is won't let me magically >run the card on +5V, but it would make me feel better knowing why I >can't :) > >Thanks, > >Josh >-- >A common mistake that people make when trying to design something >completely foolproof is to underestimate the ingenuity of complete >fools. > -Douglas Adams -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads