Hey, Peter !

October 8 2002 , you wrote:

PB> void send(BYTE word)
PB> {
PB>         int i;
PB>         for(i = 7; i >= 0; i--)         /* shift out msb first to lsb*/
PB>         {
PB>                 DATA = word & (i);      /* put but i on the data outputpin */

if you want to shift then you must do it like this:
word <<=1 // shift one bit right
or
word >>=1 // shift one bit left

using this,your FOR should look like this:
for(i=0;i<7;i++)
{
    DATA = ((word & 0x80)!=0) // 0x80 = 0b10000000
                              // bit is logic data type,so we use !=
    word <<= 1;               // shift one bit left;
    CLK = 1;
    DelayMs(5);
    CLK = 0;
    DelayMs(5);
}


PB>                 CLK = 1;                /* clock it out to the seriell_in/parallell out shiftregister */
PB>                 DelayMs(5);
PB>                 CLK = 0;
DelayMs(5) again :)
PB>         }

PB>         /* Its now out on the shiftreg */

Best regards,
 Yura                            mailto:yura_boy@mail.ru

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