Thanks for the help to all those that replied.  Lots of different solutions
for me to choice from.

Regards,
Donovan


> You've got the right idea. Here is a simple solution:
>
>      for(i = 0; i < 6; i++)
>          SCI_PrintByte(  ( (char *) &gPacket)[i] );
>
> Bob Ammerman
> RAm Systems
>
>
> ----- Original Message -----
> From: "Donovan Parks" <dparks@UVIC.CA>
> To: <PICLIST@MITVMA.MIT.EDU>
> Sent: Sunday, August 11, 2002 2:09 AM
> Subject: [PIC]: Hi-Tech C / C Question: Accessing Bytes in a struct
>
>
> > Hello,
> >
> > I'm hoping there is a Hi-Tech C / C guru here that can give me a hand.
> What
> > I have is the following struct:
> >
> > struct PACKET  // structure to hold incomming packets
> > {
> >      BYTE packetLen;
> >      BYTE msgType;
> >      BYTE msgContents[MAX_CONTENTS_SIZE];
> >      BYTE checksum;
> > } gPacket={0, 0, {0}, 0};
> >
> > Now, what I would like to do is print off each byte in this struct
without
> > having to access them using the "." operator.
> >
> > I can obviously do this:
> >     SCI_PrintByte(gPacket.packetLen);
> >     SCI_PrintByte(gPacket.msgType);
> >     ...
> >     ...
> >
> > But, what I am hoping for is something like:
> >     for(i = 0; i < 6; i++)
> >         SCI_PrintByte(*(&gPacket+i));    // this does not work! -> is
> there
> > something that will?
> >
> >
> > &gPacket should give me the address of the gPacket structure and the "*"
> > operator should then given me the value at that address.  I receive a
> > compiler error indicating I am going an "illegal conversion".  Anyone?
> > Thanks.
> >
> > Regards,
> > Donovan Parks
> >
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