I'm not exactly sure where the illegal conversion is, but your code wouldn't
work anyway, because gPacket is of type struct PACKET, so if you add 1 to it,
you will actually add the length of the struct, not just one byte. This allows
arrays of structs to easily be iterated over.

I would do something like this:

...
    char *cp;
    cp = (char *) &gPacket;
    for (i=0; i<6; i++) {
        SCI_PrintByte(*cp++);
    }
...

Regards,
Simon.
---

On Sat, Aug 10, 2002 at 11:09:55PM -0700, Donovan Parks wrote:
> Hello,
>
> I'm hoping there is a Hi-Tech C / C guru here that can give me a hand.  What
> I have is the following struct:
>
> struct PACKET  // structure to hold incomming packets
> {
>      BYTE packetLen;
>      BYTE msgType;
>      BYTE msgContents[MAX_CONTENTS_SIZE];
>      BYTE checksum;
> } gPacket={0, 0, {0}, 0};
>
> Now, what I would like to do is print off each byte in this struct without
> having to access them using the "." operator.
>
> I can obviously do this:
>     SCI_PrintByte(gPacket.packetLen);
>     SCI_PrintByte(gPacket.msgType);
>     ...
>     ...
>
> But, what I am hoping for is something like:
>     for(i = 0; i < 6; i++)
>         SCI_PrintByte(*(&gPacket+i));    // this does not work! -> is there
> something that will?
>
>
> &gPacket should give me the address of the gPacket structure and the "*"
> operator should then given me the value at that address.  I receive a
> compiler error indicating I am going an "illegal conversion".  Anyone?
> Thanks.
>
> Regards,
> Donovan Parks
>
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