BYTE *data = (BYTE *)&gPacket; // converts to pointer to BYTE

for (int a = 0; a < sizeof(PACKET); a++) // cycles through bytes
{
  SCI_PrintByte(data[a]);
}

-Kieren

----- Original Message -----
From: "Donovan Parks" <dparks@UVIC.CA>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Sunday, August 11, 2002 7:09 AM
Subject: [PIC]: Hi-Tech C / C Question: Accessing Bytes in a struct


> Hello,
>
> I'm hoping there is a Hi-Tech C / C guru here that can give me a hand.
What
> I have is the following struct:
>
> struct PACKET  // structure to hold incomming packets
> {
>      BYTE packetLen;
>      BYTE msgType;
>      BYTE msgContents[MAX_CONTENTS_SIZE];
>      BYTE checksum;
> } gPacket={0, 0, {0}, 0};
>
> Now, what I would like to do is print off each byte in this struct without
> having to access them using the "." operator.
>
> I can obviously do this:
>     SCI_PrintByte(gPacket.packetLen);
>     SCI_PrintByte(gPacket.msgType);
>     ...
>     ...
>
> But, what I am hoping for is something like:
>     for(i = 0; i < 6; i++)
>         SCI_PrintByte(*(&gPacket+i));    // this does not work! -> is
there
> something that will?
>
>
> &gPacket should give me the address of the gPacket structure and the "*"
> operator should then given me the value at that address.  I receive a
> compiler error indicating I am going an "illegal conversion".  Anyone?
> Thanks.
>
> Regards,
> Donovan Parks
>
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