Matt Pobursky said.. > You'll never get more than about 4.4V at the emitter of the transistor, > since the PIC can only supply ~5V of base drive to the transistor. Use > a PNP transistor (or P channel FET) with NPN driver stage (or N channel > FET) to supply the regulator circuit. > > Thanks for the help..but I don't understand why I will only get 4.4v. I thought that if I supply 5v to the NPN base from a logic high PIC output pin, the transistor would act as a simple switch and pass the +9v across the C-E junction. Why only 4.4v? Thanks Les -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads