> One other thing that's got my head spinning; assuming I've got a pure 5v
> power supply.. now, the PIC datasheet says the chip consumes 20uA
typically
> (at 3V but lets just assume its the same).  Even without using Ohm's Law
> it's clear to see that I=V/R is going to be really quite large.  Is my
> assumption correct therefore when I assume that the chip is basically just
a
> resistor?

No!  It draws 20uA in a particular case.  Its current draw can change
dramatically and quickly.  When running, it will require much more than
20uA.


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