Yay! ^_^  You must excuse me, I think I'm on a sugar high.
Okies, just thought of another question (after the natural "what's a cct")..
If I wanted to use a 5V PIC that uses < 0.6mA typically to switch on/off a
6V, 30mA laser module (I like lasers they're pretty), well.. how would I do
it? :)  Obivously I'd need a 6V (or more) source, no?  Would I then use a
voltage divider on one end to drive the PIC.. the laser would run off the
other parallel-ly connected circuit, but how would an outpin pin from the
PIC switch it?  I'm thinking "relay" but also "maybe that's a bit bulky".  A
transistor?  How would I connect it? :)

-Kieren


----- Original Message -----
Wrom: CONEUQZAAFXISHJEXXIMQZUIVOTQNQEMSFDULH
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Thursday, July 11, 2002 8:20 PM
Subject: Re: [EE] Will the questions never end?! ;) (small attachment)


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> Yes.  It would be 10V  That's what parrallel ccts are all about.
>
> - --Brendan
>
>
> > Hi,
> >
> > I've been studying my introductory textbooks for a while now,
> > getting this one theory right would be a milestone for me.  I've
> > attached a .gif of the question in question :D.  Basically, if I
> > have two circuits, connected in parallel to a source (lets say a
> > 10V battery), and voltage-divide on one of them with resistors, can
> > I create 2 off-coming voltages of (lets say for example) 4V and
> > 6V... and then, could I still get a 10V supply from the other
> > connected circuit (same source), and divide that as I saw fit? :)
> > If this is true, am I to assume that in general, people use 2
> > small, different value resistors in series, and run a load in
> > parallel with one of them to lower voltages? :D
>
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> dn6/ApYp1R3IgaF7tcX66B46
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