> Integrate the waveform over the duration of a single flash sequence, then
> square the result, and multiply by 10 ohms, then, as long as you carry the
> units through, you have an output in watt-seconds^2  sot hen divide by the
> time it takes for the strobe sequence, which gives watt-seconds, which is
> what you wanted, right?

I haven't worked out what this mess results in, but I doubt anything
relevant.  There are so many errors here, I don't know where to begin.

First, I think your intent was to find RMS voltage (the "waveform"?) accross
the resistor, then calculate power because you know the resistance.  Even if
this had been done correctly, it would only tell you the power going into
the resistor, not the power into the load under test.  The power into the
resistor is a function of load current only.

Second, integrating the voltage accross the resistor, then squaring it does
not produce a meaningful value here.  To get RMS, you start by integrating
the square, not squaring the integral.  You then have to take the square
root.  I assume you omitted this step because you wanted the square of the
voltage accross the resistor.

Third, power into a resistor is V**2 / R.  You are trying to compute V**2 *
R, which is certainly not a unit of power.

Fourth, you are assuming the power draw is synchronized with a flash.  This
would need to be proven first of course, but is highly unlikely.  Power draw
is much more likely to be synchronized with the power cycles, although the
amount drawn each power cycle probably is a function of the number and
strength of flashes since the previous peak power draw.  I would set the
strobe to flash at a rate much higher than the power line frequency, and
then ignore the effect of individual flashes.  The power draw should then be
smoothed out by the filter caps in the power supply.


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