> Scott can probably come up with something that takes 1 instruction or
less,
> but how about this:
>
>     bsf   status, c    ;set value of bit to shift in
>     rlf   x            ;shift left 1 (*2), shift in 1 (+1)

It occurred to me later that the following is different but just as valid:

    rlf   x            ;shift left 1, low bit unknown
    bsf   x, 0         ;explicitly set the low bit to 1


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