You'd use an transformer with an RMS voltage at rated current that was a
lower voltage than the target 9.0VDC?  That's different from what I've
done in the past but I'm always willing to learn new stuff.  Can you
quote the Engineering text book where this is taught from?  I'd like to
add that to my library.  Got to be some other good stuff in it too.

John



Wireless CAN with the CANRF module.
http://www.autoartisans.com/documents/canrf_prod_announcement.pdf
Automation Artisans Inc.
Ph. 1 250 544 4950


> -----Original Message-----
> From: pic microcontroller discussion list
> [mailto:PICLIST@MITVMA.MIT.EDU] On Behalf Of Olin Lathrop
> Sent: Friday, May 31, 2002 12:39 PM
> To: PICLIST@MITVMA.MIT.EDU
> Subject: Re: [PIC]: Caps select for PSU
>
>
> > In the above example,  the desired voltage is 9V but there
> is the diode
> > and regulator and what we want into the input of the regulator is 2V
> > higher than the 9V => 11V.  Next there is that pesky diode
> voltage drop
> > through the bridge. Another 1.2V => 12.2V therefore in reality the
> > _desired_ RMS transformer voltage is 12.2V
>
> This is also wrong.  12.2 is the minimum *peak* voltage the
> transformer must
> put out, which allows for no ripple at all.  The RMS
> transformer voltage
> would be 12.2 / sqrt(2) = 8.6V.
>
>
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