> I suspect you will need to be a bit more proactive about how you detect the
> first character. For example take the character 'A', that is binary
> 01000001, and consider how this will be received at the wrong baud rate.
>
> case 1 - character seen in your test is 10011111 or 00001111 then baud rate
> at the receiving end is probably half the transmitted baud rate.

Ok, I got this one, but why are the rest 1 and not 0?
>
> case 2 - character seen at receiving end is 00011000 then baud rate at
> receiving end is probably twice the transmitter. (stop and think about why
> there is an extra 0 at the left hand end).

I can't find a good answer...
>
> case 3 - character seen at receiving end is 00000001 then baud rate at
> receiving end is probably 4 times the transmitted baud rate. (again think
> about what happens with the start bit).

If there is one extra 0 in the beginning like in case 2, why isn't it
00000111?
>
I tried to compare with those but the only one working was the baud
rate I started with. I think the program didn't get out of the loop that
receives the first byte.

> If you can arrange to measure the bit widths on the pin then you will
> probably arrive at the required baud rate a lot quicker.

Exactly what do you mean?

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