I did this recently with a PIC 16F872. A 5V regulator drops the ~12V down to the operating voltage of the PIC, as well as providing the reference voltage. The input is simply a voltage divider on the ~12V supply to limit the voltage going into the PIC. Actually I set it up so 25.5V at the input will divide down to 5V. This way, 25.5V reads 255 on the top 8 bits of the A/D and I saved myself some math that way. But I do lose a bit of resolution (not a big deal). Also have upper and lower alarms settable with a single-button interface. Cheers, -Neil. -----Original Message----- From: pic microcontroller discussion list [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Tal Bejerano - AMC Sent: Wednesday, May 22, 2002 5:35 PM To: PICLIST@MITVMA.MIT.EDU Subject: [EE]: Voltage Compare Hi All I want to measure and get a warning if car battery is drop under 11.5v. look at some circuits that use op-amps/comparators and read the explanations and I wonder, how can it work? if the circuit use the battery voltage to operate and the voltage drops, then all the adjustments are not correct. as I understand it I need 2 voltage sources: one is stable and the other is the battery I monitor. ??????? Regards Tal Bejerano AMC - ISRAEL -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads