On Mon, 6 May 2002, Jinx wrote:

> > Since 10,000 in decimal is 0x2710 why not just do the 0x10+1
> > (i.e.0x11) and be done with it
>
> Yes, I could do that. I'm still trying to pull that code apart, and
> would prefer it if I could at least assemble it so as to run it. So
> at a guess (uninformed at this stage) I presume the original
> expression is there to show how the 10+1 is derived from
> right-shifting the 10,000

Actually, 0x2710>>8 +1 is 0x27+1 = 0x28.

The output(temp) is a carry over from the original author's
implementation. You can safely change this to:


   call   output_temp


...


output_temp:

   ; write some code to take the BCD coded value
   ; in the variable 'temp' and write some it some
   ; where (like an LCD).


Scott

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