> Since 10,000 in decimal is 0x2710 why not just do the 0x10+1
> (i.e.0x11) and be done with it

Yes, I could do that. I'm still trying to pull that code apart, and
would prefer it if I could at least assemble it so as to run it. So
at a guess (uninformed at this stage) I presume the original
expression is there to show how the 10+1 is derived from
right-shifting the 10,000

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