not knowing much about the C compiler being used, how about:

void my_lcd_putc(byte c)
{
    lcd_send_byte(rs,c);
}

int d;
void main()
{
    printf(my_lcd_putc, "Here is an integer: %d", d)

}

or some such....

Bob Ammerman
RAm Systems


----- Original Message -----
From: "Dale Botkin" <dale@BOTKIN.ORG>
To: <PICLIST@MITVMA.MIT.EDU>
Sent: Tuesday, March 19, 2002 7:35 AM
Subject: Re: [PIC]: displaying a value on LCD


> On Tue, 19 Mar 2002, MATTHEWS, DEAN (D.) wrote:
>
> > Dale,
> >
> > Im extremely confused, again! I am sending bytes of data into the Lcd
> > as nibbles(using 4 data pins and two control pins) and not serially
> > using the following function:
> >
> > void lcd_send_byte(byte rs, byte n)
> > {
> > port_c=rs;
> > delay_ms(500);
> > lcd_send_nibble(n>>4);
> > lcd_send_nibble(n&0xf);
> > }
>
> Hmmm.  Are you using the CCS LCD driver file, lcd.c?  It looks like you
> might be, since that file includes lcd_send_nibble().  If so, it's also
> got an lcd_putc() function you can use to save yourself some tmie and
> effort.  I'm not sure what the rs parameter of the function above is
> doing, but lcd_send_byte() needs two parameters.  I think sending printf()
> output to a function will only work with a function that takes a single
> parameter -- printf()  will call it once for each character in the
> resulting output.  Doing this:
>
> printf(lcd_putc,"value in memory is %02x",NUMBER);
>
> should get you there, assuming you have a function lcd_putc() that takes a
> character as a single parameter and spits it out to the LCD.
> Alternatively, if the port_c=rs bit is impoprtant you could maybe do
> something like this:
>
> ***WARNING*** untested code ahead!
>
> char x = 0;
> char buffer[25];
> sprintf(buffer,"value in memory is %02x",NUMBER);
>         // puts output string in buffer
> while(buffer[x] lcd_send_byte(rs, buffer[x++]);
>         // calls lcd_send_byte for each character in buffer
>
> Dale
>
> --
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>

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