Put resisters inline, and then diodes going to the power supply (+5 or +3.3). The resisters limit the current, and the diodes shunt voltages a little above your power supply to your power supply (which, hopefully, will handle it and still regulate properly). This is essentially what the pic does, look in the data sheets for the schematics of the ports on the pic. Many a hobbyist has sat in wonder at seeing their pic last through some stupid connection mistake.... -Adam Micro Eng wrote: > looking for a way to protect an I2C mux. We have two RJ45 connectors, > one > with serial, one with I2C. If they plug them in wrong, then it could > (and > probably did) blow the mux. So is there a way to protect this? Next > design > will fix it by not allowing 12V on one of the I2C pins but for now we > can't > change the connectors/wiring scheme. > > > _________________________________________________________________ > Send and receive Hotmail on your mobile device: http://mobile.msn.com > > -- > http://www.piclist.com hint: PICList Posts must start with ONE topic: > [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads > > > > > -- http://www.piclist.com hint: PICList Posts must start with ONE topic: [PIC]:,[SX]:,[AVR]: ->uP ONLY! [EE]:,[OT]: ->Other [BUY]:,[AD]: ->Ads