Hi Thomas. Strcat takes a char * not a char. However, you can't just
say: (char *)&day because you can't know that it will be zero
terminated. Same for year.

There are lots of ways you might do this depending on your platform. On
a big computer (big being a PC or something) you might just use
sprintf():

sprintf(bd_string,"%d %s %d",day,month,year);

But most small computers won't like sprintf much.

 char *bp=bd_string;
 char *mp=month;
 if (day>=10) *bp++=day/10+'0';
 *bp++=day%10+'0';
 *bp++=' ';
  while (*mp) *bp++=*mp++;
 *bp++=' ';
 *bp++=year/1000+'0';
 *bp++=(year%1000)/100+'0';
 *bp++=(year%100)/10+'0';
 *bp++=year%10+'0';

I didn't test that but it ought to work for years <9999.

Al Williams
AWC
* 8 channels of PWM
http://www.al-williams.com/awce/pak5.htm



> -----Original Message-----
> From: pic microcontroller discussion list
> [mailto:PICLIST@MITVMA.MIT.EDU] On Behalf Of Thomas N
> Sent: Friday, March 08, 2002 3:35 PM
> To: PICLIST@MITVMA.MIT.EDU
> Subject: [OT]: strcat in c language. Please help!
>
>
> Hello everyone,
>
> Here is my short program:
> void main( void )
> {
>         int day = 1,
>                 year = 2002;
>         char month[6] = "May",
>                 bd_string[60] = {'\0'};
>
>         strcat(bd_string, (char) day);
>         strcat(bd_string, month);
>         strcat(bd_string, (char) year);
> }
> What I am trying to do is to copy "1 May 2002" into the
> string "bd_string". I try as above and it doesn't work.
> Please help! Thank you! Thomas.
>
>
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