At 01:36 PM 3/8/02 -0500, you wrote:


>Supply Voltage: 4.7 to 7.00 Vdc
>Output Voltage (Ratiometric): 0.500 (10.060) Vdc at 0 PSI 4.500 (10.060) Vdc
>at Full Scale
>
>So, if the pressure is half of the Full Scale, the output voltage is (0.5 +
>4.5) / 2 = 2.5V. Since the sensor is ratiometric and it operates on 5V,
>therefore the output voltage is actually half of the supply voltage (2.5 / 5
>= 0.5). That means that if the supply voltage changes to 6V, the output
>voltage becomes 3V. Right?

Yes, assuming the sensor to be linear! If you're digitizing this it's often
best to use a single reference voltage for both the A/D and the sensor. If
you have a clean enough supply voltage of high enough accuracy, that
reference may be the supply voltage (as can be done with PIC A/Ds). Then
the reference voltage cancels and you'd get a count of 0x200 +/- from a
10-bit A/D at half-scale (output voltage, maybe input pressure) regardless
of the exact reference voltage.

Best regards,

Spehro Pefhany --"it's the network..."            "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog  Info for designers:  http://www.speff.com
9/11 United we Stand

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