> OK, what exactly does this "->" operator accomplish?  My book
> says it is a
> "structure pointer operator", which might as well say it was
> a Left Handed
> Metric 1" Macedonian Rubber-headed Fiddle Wrench and I'd
> still be none the
> wiser.

Shorthand, effectively.

When working with a struct, referencing an element of a struct us done using
dot notation.

i.e.

struct mystruct s;

s.element

When working with a pointer to a structure -

struct mystruct *s;

to access the element, you can use...

(*s).element

or, preferably

s-> element

Reference - K&R, 6.2 (p131 in my edition)

I think I have the manual for the rubber-headed fiddle wrench somewhere,
too.

HTH

Peter
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