Donovan,


 It seems to me that if your motor produces 550 Ft/Lbs of torque, then
 it would exert a force of 550 lbs at a distance of 1 foot from the center
 axis of the motor shaft.  And if the free end point of the lever on the
 motor shaft were connected to a load cell, then the load cell should
 report 550 lbs of force.  If you shortened the lever to say 6 inches, you
 would double your torque, and therefore your force, so in that case, the
 load cell should report 1100 lbs of force.

 Is this thinking wrong?  Is it not this straight forward?  I believe this
 is correct.   I'd be interested in finding out the results of your
 experiments (Tests).


                                                    Regards,

                                                      Jim









> Hello,
>
> I have a 1 HP motor (= 0.75kW = 553 foot lbs/sec) and need to know how
> much force it can exert.  I am looking for a 'best case' estimate -
> that is, what is the most force it can exert if everything where ideal.
>  What I am thinking, is that if I have a load cell fixed to a wall then
> what will it read.
>
> Power = Work / time = Force * distance / time
>
> So, Force = Power * time / distance
>
> At this point, my physics fails me.  Certainly the time the motor acts
> on my load cell will not effect the measurement and there is no
> distance travelled.... help - where am I going wrong.
>
> Regards,
> Donovan Parks
>
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