Hi Josh, Good to see my idea validated by Roman :) The reason I split the current limiting resistors for the LED was to provide some protection to the PIC for Electro-Static discharge and short circuits in the cable. To fulfil these requirement, they MUST be located at the PIC. And for ease of assembly, the other resistors should be there as well I'd assume. I don't think you'll get any benefit moving them to the end of the cable. Roman, this is the circuit I posted: 120 > PIN1 >-----------/\/\/\--, > | > 10K Bi Colour LED > Vcc >--/\/\/\-, | > | 120 | > PIN2 >---------+-/\/\/\--+ > | > 0 | > 0 | Switch > 4.7K | > GND >--/\/\/\-----------' --- Ashley Roll Digital Nemesis Pty Ltd www.digitalnemesis.com Mobile: +61 (0)417 705 718 > -----Original Message----- > From: pic microcontroller discussion list > [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Josh Koffman > Sent: Wednesday, 6 February 2002 9:03 AM > To: PICLIST@MITVMA.MIT.EDU > Subject: Re: [PIC]: Driving a dual LED > > > As an afterthought, would it help to put the resistors in the remote? > Other than the pullup resistor of course. > > Josh > -- > A common mistake that people make when trying to design something > completely foolproof is to underestimate the ingenuity of complete > fools. > -Douglas Adams > > Roman Black wrote: > > > > I had a think about it and this only took me about > > 30 seconds (1st doodle). :o) > > > > Solution: (3 resistors, no parts in remote) > > > -- http://www.piclist.com hint: To leave the PICList mailto:piclist-unsubscribe-request@mitvma.mit.edu