On Mon, 4 Feb 2002 14:29:55 -0800, Andrew Warren wrote:

>Bob Barr wrote:

<snip>

>>
>> In either case, you can remove the BTFSC's and the MOVLW's following
>> them since the BTFSC will always skip the MOVLW. Bit 6 of your digit's
>> ASCII will always be clear for decimal digits '0' through '9'.
>
>    True, but it'll be set for hex digits 'A' through 'F'.
>
>    If the two input bytes are hex digits in the range 0-F, you need
>the
>    BTFSC/MOVLWs; if they're only in the range 0-9, you don't.
>

Andy,

The input digits do have to be in the ASCII '0'-'9' range (otherwise
doing the '* 10' wouldn't be right.)

Royce's original input data is a pair of decimal characters to be
converted to hex. The characters 'A' through 'F' just can't be part of
valid input data.


Royce,=20

Do you need your result in BCD form (for displaying the two digits) or
in its true hex form (for indexing a table or some such)?



Regards, Bob

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