16bit * 3 = 2bytes * 3 = 1word * 3
Even without cc5x sounds pretty easy to shift out one byte ( you have 6
bytes ). With a counter number the byte lenght ( 8 ). There are also
some smart tehniques of testing the high order bit of the shifted byte
instead of use another register for counting. ( Scott Datalo is a master
of this trick ). Then perform a left or right shift starting with lsb or
msb as you wish. Test the bit which will be shifted and toggle the output
line only if there is a diference with the previous value. Repeat the
algorithm for all bytes involved.

hope it helped you,
Vasile

On Wed, 30 Jan 2002, [iso-8859-1] Simon-Thijs de Feber wrote:

> Hello All,
>
> I need to shift out to a pin a large number of bits
> (16b * 3 ). Since i am using CC5X (does it have 16 bit
> variables ???) i was wondering if this could be
> implemented easily !?
>
>
> grtz
>
> Simon
>
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