> OK, But given what you have said above, inverting the logic
> would also do the trick, would it not?

IMHO the resistor should take the pin to the LED's off-state,
ie pull the pin high if LED (anode to Vcc, cathode to pin)
current is sink, pull the pin low (LED anode to pin, cathode
to 0V) if current is source.

A pull-down with the way you have the LED now (sink) will
use unnecessary power, as the off-state is with the pin high.
A pull-up will immediately tie the pin high when power is
applied, effectively putting both a and k of the LED at 5V,
so there should be no blip

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