> And consider this Wouter - you would need 70A of DC to
> display worst-case "88:88", assuming 7 x 4 x 120 LEDs
> pulling 20mA each. A 25A supply for each digit ? Not trying
> to put you off (especially as LEDs are "in" these days), but I
> got a surprise when I did the calcs for my request

The customer only wants two digits, and I guess I can put at least 5 in
series, so that would be 7 x 2 x 120 x 0.02 / 5 = 6.72 A. No problem for a
car race environment where accu's are found all over the place. But how
large were your digits?

Wouter

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