Is the following bit of code valid for continuously digitizing an 8-bit
value on channel 0 and a 10 bit value on channel 1? My main question is
about the for() loop: whether this is a valid method to get 10 bit =
resolution
with an 8 bit adc and whether or not there should be any additional =
delays
in this loop. Delays are only needed when you open up the channel mux, =
right?


thanks,
Rob


   unsigned char value0;    // 8 bit resolution
   unsigned short value1;   // 10 bit resolution
   unsigned char channel;
   unsigned char i;


   // initialize a/d:

   channel =3D 0;
   ADCON0 |=3D (channel << 3);   // open channel 0
   delay();                    // delay 50 microseconds

   // main loop:

   while(1)  {
      // do other things
      digitize();              // gets here after at least 50 =
microseconds
      // do other things
   }


   void digitize()  {

      ADGO =3D 1;
      while(ADGO) {}

      if (channel=3D=3D0)  {
         value0 =3D ADRES;
         channel =3D 1;
      }
      else  {
         value1 =3D ADRES;       // first digitization

         for(i=3D0;i<3;i++)  {
            ADGO =3D 1;
            while(ADGO) {}
            value1 +=3D ADRES;
         }

         // do I have a valid 10 bit 'value1' here? (up to a count of =
1020)

         channel =3D 0;
      }


      ADCON0 |=3D (channel << 3);    // open next channel for next pass
      return;
   }

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