On Tue, 4 Dec 2001 09:30:14 +1000, you wrote:

>Hi
>
>typedef union {
>        struct {
>                int Bit0 : 1;
>                int Bit1 : 1;
>                int Bit2 : 1;
>                int Bit3 : 1;
>                int Bit4 : 1;
>                int Bit5 : 1;
>                int Bit6 : 1;
>                int Bit7 : 1;
>        } Bits;
>        unsigned char Value;
>} BitDataByte;
>
>BitDataByte myData;
>
>myData.Value =3D 42;
>
>myData.Bits.Bit0 =3D 1;

Could you then simplify the access to the bits by doing=20
#define modeflag myData.Bits.Bit0
modeflag=3D0;
etc.  ?

Could you also simplify the above declaration by using=20
bit Bit0;
instead of int Bit0:1;


>Will get you started.. the ": 1" tells the compiler to allocate 1 bit to=
 the
>element, but you can allocate any number. So you can have a 2 or 3 or 14=
 bit
>number as you choose. more details should be in your local C language =
book
>:)
>
>Cheers,
>Ash.
>
>---
>Ashley Roll
>Digital Nemesis Pty Ltd
>www.digitalnemesis.com
>Mobile: +61 (0)417 705 718
>
>
>
>
>> -----Original Message-----
>> From: pic microcontroller discussion list
>> [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Sean H. Breheny
>> Sent: Tuesday, 4 December 2001 8:47 AM
>> To: PICLIST@MITVMA.MIT.EDU
>> Subject: Re: [pic]:Accessing a var as a byte or bits in C
>>
>>
>> What is the syntax? I've been using C for 9 years (mostly on
>> PCs but also
>> on microcontrollers) and don't recall ever seeing it!
>>
>> Sean
>>
>> At 03:43 PM 12/3/01 -0500, you wrote:
>> >Normal C has bitfields in it. Usually you use them in
>> structs or unions.
>> >Problem is you don't usually know which bit is assigned, so I prefer
>> >assembly at that level of detail.
>> >/\/\/\/*=3DMartin
>>
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