"Scott F. Touchton" schrieb:
>
> I don't think you would find me a receptive business partner....
>
> Here is where I get confused in the conversation... a single car has the
> energy of 1/2 mv^2.  Two cars of identical mass have the combined energy of
> mv^2.
>
> So, if one is traveling towards the other, they each impart 1/2mv^2 to the
> total impact.
>

After this, they don't move. so energy==0

> Now, if you bring in the relative part, one car standing still and the
> other traveling at 2V, now the energy is 2mv^2 (not the earlier assumption
> of mv^2).
After this, both move with 75 kph (1V), so half of the doubled energy is
still there.....no nobel prize for physics..... ;-(

Greets
Jochen Feldhaar

>
> I am totally perplexed in this right now.. I would gather that one
> assumption is wrong (of course, or I made a stupid math error).
>
> Please find it in your heart to enlighten me... I actually lost sleep over
> this!!
>
> Scott
>
>                     Bob Ammerman
>                     <rammerman@ADE       To:     PICLIST@MITVMA.MIT.EDU
>                     LPHIA.NET>           cc:
>                     Sent by: pic         Subject:     Re: [ot]: how does a radar detector work?
>                     microcontrolle
>                     r discussion
>                     list
>                     <PICLIST@MITVM
>                     A.MIT.EDU>
>
>                     11/07/01 11:54
>                     PM
>                     Please respond
>                     to pic
>                     microcontrolle
>                     r discussion
>                     list
>
> ----- Original Message -----
> From: "Scott F. Touchton" <Scott.Touchton@US.JDSUNIPHASE.COM>
> To: <PICLIST@MITVMA.MIT.EDU>
> Sent: Wednesday, November 07, 2001 6:12 AM
> Subject: Re: [ot]: how does a radar detector work?
>
> > Energy is relative to velocity and mass.  So... one car traveling at
> 75mph
> > will impart energy equating to the square of its velocity and mass.  If
> you
> > hit another car traveling towards you at 75mph, it is the same as hitting
> a
> > fixed object at the relative speed, 150mph.  Much more energy... I was
> > wrong about the twice part, it is a squared relationship.  So you have 4
> > times the energy being imparted onto both cars (so each will see twice as
> > much if the masses are the same).
> >
> > Scott F. Touchton
> > 1550 Engineering Manager
> > JDS Uniphase
>
> Again, where does this energy come from? If you can tell me, I'd like to go
> into business with you selling perpetual motion machines.
>
> Bob Ammerman
> RAm Systems
>
> >
> >
> >                     Gerhard
> >                     Fiedler              To:     PICLIST@MITVMA.MIT.EDU
> >                     <gfiedler@GLOB       cc:
> >                     O.COM.BR>            Subject:     Re: [ot]: how does
> a
> radar detector work?
> >                     Sent by: pic
> >                     microcontrolle
> >                     r discussion
> >                     list
> >                     <PICLIST@MITVM
> >                     A.MIT.EDU>
> >
> >
> >                     11/06/01 10:29
> >                     AM
> >                     Please respond
> >                     to pic
> >                     microcontrolle
> >                     r discussion
> >                     list
> >
> >
> >
> >
> >
> >
> > At 09:54 11/06/2001 -0500, Scott F. Touchton wrote:
> > >I have to disagree with you... you have approximately twice as much
> energy
> > >being absorbed by the cars.
> >
> > Twice as much by _two_ cars... :)  If you run one car into a completely
> > (ideally) stiff wall, it's the energy of one car absorbed by one car,
> > because the stiff wall doesn't absorb anything, so in this two cases,
> every
> > car absorbes the same energy, no matter whether it's one car against a
> wall
> > or two cars against each other. (A different thing is a car against a
> > standing car.)
> >
> > ge
> >
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