One could always do the math, it's not that difficult (hell if I can do it
then...

However, from memory for a square wave P-P = 2RMS and for a triangular wave
P-P = 2*root(3)*RMS. TTYL

> -----Original Message-----
> From: pic microcontroller discussion list
> [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of jim
> Sent: Monday, October 08, 2007 01:55
> To: PICLIST@MITVMA.MIT.EDU
> Subject: Re: [EE]: RMS Voltage to PP Voltage Conversions
>
>
> Well, for the sine wave,  RMS to P-P,  is RMS*2.828.
> I'm not sure of the others though.   I'd look at them on a
> scope and see what the P-P value is.
>
>
>
>                                             Regards,
>
>                                                 Jim
>
>
>
>
> ----- Original Message -----
> From: Donovan Parks <dparks@UVIC.CA>
> To: <PICLIST@MITVMA.MIT.EDU>
> Sent: Sunday, October 07, 2001 7:10 PM
> Subject: [EE]: RMS Voltage to PP Voltage Conversions
>
>
> > Hello,
> >
> > I need to convert some RMS voltage readings to PP
> (peak-to-peak) voltages.
> > The waveforms being used are a sinusodial, square, and triangle.  Does
> > anyone know the conversions for these waveforms?
> >
> > Thanks,
> > Donovan Parks
> >
> > --
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