Olin, I think what you meant to say originally was that the CATHODE should be moved to the other side of the resistor. Foster > -----Original Message----- > From: pic microcontroller discussion list > [mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of Olin Lathrop > Sent: Tuesday, October 02, 2001 7:21 AM > To: PICLIST@MITVMA.MIT.EDU > Subject: Re: [EE]: Powering LEDs from AC power line. > > > > But if you move the anode side, without moving the > > cathode, the diode is no longer in reverse parallel > > with the LED. For tat matter, it wouldn't be parallel > > with the LED at all. Wouldn't that defeat the purpose > > of putting it in the circuit? > > The diode is still reversed accross the LED with a resistor in between. > With the diode directly accross the LED, the cap charges/discharges both > ways thru the resistor. With the diode accross the resistor and > LED instead > of just the LED, the cap charges without the resistor on the > negative slope. > The cap current then goes thru the resistor and LED on the positive slope. > This is a little more efficient because the current only goes thru the > resistor once. > > > ******************************************************************** > Olin Lathrop, embedded systems consultant in Littleton Massachusetts > (978) 742-9014, olin@embedinc.com, http://www.embedinc.com > > -- > http://www.piclist.com#nomail Going offline? Don't AutoReply us! > email listserv@mitvma.mit.edu with SET PICList DIGEST in the body > > > -- http://www.piclist.com#nomail Going offline? Don't AutoReply us! email listserv@mitvma.mit.edu with SET PICList DIGEST in the body