At 10:27 PM 9/26/01 -0400, you wrote:

>3: Read the input. If it is high then the switch must be closed because the
>capacitor is
>    discharging thru the 47K. If it is low then the switch is open.

I don't think this will work because of the effective 300R to ~3V (the
resistor/LED) swamps the 47K resistor.

Maybe you could do it with the output impedance of the PIC port pin and
the capacitor time constant, but..

Best regards,

Spehro Pefhany --"it's the network..."            "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog  Info for designers:  http://www.speff.com
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