I(peak) = T/T1 * Idc

Where T = 1/f (1/50 for 1/2 wave and 1/100 for full wave) - or 1/60 and 1/20
depending where you are.
T1 = conduction angle of diodes
Idc = average current.

Also, Xc = 1/(2*pi*f*C) and average current = Vrms/Xc

Regards

David Huisman

-----Original Message-----
From: pic microcontroller discussion list
[mailto:PICLIST@MITVMA.MIT.EDU]On Behalf Of David VanHorn
Sent: Tuesday, 11 September 2001 6:03
To: PICLIST@MITVMA.MIT.EDU
Subject: Re: [EE]:Power transformer question


At 03:03 AM 9/11/01 +1000, Roman Black wrote:
>David VanHorn wrote:
> >
> > Rusty neurons here:
> >
> > How do you calculate peak diode current in a full wave or bridge power
> supply?
> >
> > I know it's based on the cap size, which determines the ripple voltage,
but
> > I don't remember the diode peak current part.
>
>
>Put a 0.1 ohm resistor in series and look on the CRO.

I'd snap a current probe on it if it existed yet.
Unfortunately, I'm in the position of having to develop a spec.
It's further complicated by some design variables that take the required
current output over a pretty wide range.

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